There are two new vocabulary terms that may appear in application problems.
Angle of Elevation:
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In this diagram, xº marks the
angle of elevation of the top of the tree as seen from a point on the ground. |
The angle of elevation is always measured from the ground up. It is an upward angle from a horizontal line. It is always inside the triangle.
You can think of the angle of elevation in relation to the movement of your eyes. You are looking straight ahead and you must raise (elevate) your eyes to see the top of a tree.
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Angle of Depression:
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In this diagram, xº marks the
angle of depression of the boat at sea from the top of the lighthouse. |
The angle of depression is always OUTSIDE the triangle. It is never inside the triangle. It is a downward angle from a horizontal line.
You can think of the angle of depression
in relation to the movement of your eyes. You are standing at the top
of the lighthouse and you are looking straight ahead. You must lower (depress) your eyes to see the boat in the water.
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Notice
how the horizontal line in the angle of depression diagram is PARALLEL
to the ground level. The fact that horizontal lines are always parallel
guarantees that the alternate interior angles are equal in measure. In
the diagram, the angle marked xº is equal in measure to
m∠BAC. Simply stated, this means that ... → the angle of elevation = the angle of depression ← |
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When solving a problem with an angle of depression you need to find the measure of an angle INSIDE the triangle. There are two options:
Option 1: find the angle inside the triangle that is adjacent (next door) to the angle of depression. This adjacent angle will always be the complement
of the angle of depression, since the horizontal line and the vertical
line are perpendicular (90º). In the diagram at the left, the adjacent
angle is 52º.
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Option 2: utilize the fact that the angle of depression = the angle of elevation and label ∠BAC as 38º inside the triangle.
Notice that both options, the answer is the same. |
Let's see how to put these skills to work in word problems.
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SOLUTION:
• A "guy" wire is a support wire used to hold a newly planted tree in place, preventing it from bending or up-rooting during high winds. • The "angle of elevation" is from the ground up. • It is assumed that the tree is vertical, making it perpendicular with the ground. • This problem deals with "opposite" and "hypotenuse" making it a sine problem. • |
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SOLUTION:
• Remember that the "angle of depression" is from a horizontal line of sight downward. • It is assumed that the tower is vertical, making it perpendicular with the ground. • This solution will use alternate interior angles from the parallel horizontal lines, so place 40º inside the triangle by the partner (bottom right). • This solution deals with "opposite" and "adjacent" making it a tangent problem. • |
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SOLUTION:
• Remember that the "angle of elevation" is from the horizontal ground line upward. • It is assumed that the lamp post is vertical, making it perpendicular with the ground. • Shadows are on the ground! If you place the "shadow" on the hypotenuse you have created an apparition ( a "ghost"), not a shadow! • This solution deals with "opposite" and "adjacent" making it a tangent problem. • |
Not all trigonometry word problems will use the terms "angle of elevation" or "angle of depression". You may need to read carefully to see where to indicate the angle in the problem.
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SOLUTION:
• In this problem place xº where the ladder meets the wall. Do not assume that the angle will always be at the ground level. • It is assumed that the wall is vertical, perpendicular with the ground. • The foot of the ladder is the bottom of the ladder, where it hits the ground. • This solution deals with "opposite" and "adjacent" making it a tangent problem. • |
It may be the case that a problem will be composed of two overlapping right triangles.
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SOLUTION:
• Think of this problem as working with two separate triangles: (1) the larger triangle with the 40º angle and a vertical side that represents the ENTIRE height, b, of the tower, and (2) the smaller triangle with the 25º angle and a vertical side, a, that represents the height of the first (bottom) section of the tower. • Solve for the vertical heights (b and a) in the two separate triangles. • The needed height, x, of the second (top) section of the tower will be the difference between the ENTIRE height, b, and the height of the first (bottom) section, a. You will need to subtract. • In both triangles, the solution deals with "opposite" and "adjacent" making it a tangent problem. • Larger triangle with height b: • Smaller triangle with height a: • Difference (b - a): 73.00166791 - 40.56876626 = 32.43290165 ≈ 32 feet |
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